koobas.hobune.stream
Does Mathf.PingPong always have to start at (0,0,0)?
pretty much what the title asks. I copied the exaple right from the scripting reference but I noticed that u can't choose where it starts and where it ends like Lerp for example. All you can do is choose the time and the length.
Yes, like you can read in the docs it always ping-pongs between 0 and length. However if you want a different range, just add an offset. You can also create a helper like this:
// C#
float PingPong(float aValue, float aMin, float aMax)
{
return Mathf.PingPong(aValue, aMax-aMin) + aMin;
}
// UnityScript
function PingPong(aValue : float, aMin : float, aMax : float) : float
{
return Mathf.PingPong(aValue, aMax-aMin) + aMin;
}
thanks a lot. I'm gonna test it in a bit. It's a little confusing but I'll figure out which part does what when I test it.
ps: If you want a correct "mapping", you would have to subtract a$$anonymous$$in from aValue when feeding it to $$anonymous$$athf.PingPong. However usually pingpong is only used with a constantly incrementing / decrementing value so it usually doesn't matter since it just "shifts" the ping-pong pattern start by a$$anonymous$$in.
That would make more sense when using $$anonymous$$athf.Repeat to clamp a value between a $$anonymous$$ and max value.
I can't get it to work. Here's my code.
var aValue : float = 10.0;
var a$$anonymous$$in : float = 3.0;
var a$$anonymous$$ax : float = 7.0;
function Update ()
{
}
function PingPong(aValue : float, a$$anonymous$$in : float, a$$anonymous$$ax : float) : float
{
return $$anonymous$$athf.PingPong(aValue, a$$anonymous$$ax-a$$anonymous$$in) + a$$anonymous$$in;
}
goth it to work. function PingPong is confusing as hell. But I added an offset like you said and it works like I want it to. I had already tried this but I didn't know how to get it to work. Anyway here's my working code.
function Update ()
{
transform.position.z = $$anonymous$$athf.PingPong(Time.time, 15) + 5;
}
I think you got the purpose of my helper function wrong ;) $$anonymous$$y function just wraps $$anonymous$$athf.PingPong, so ins$$anonymous$$d of $$anonymous$$athf.PingPong you can use my PingPong:
function Update ()
{
// the value would ping pong between 5 and 20
transform.position.z = PingPong(Time.time, 5, 20);
}
function PingPong(aValue : float, a$$anonymous$$in : float, a$$anonymous$$ax : float) : float
{
return $$anonymous$$athf.PingPong(aValue, a$$anonymous$$ax-a$$anonymous$$in) + a$$anonymous$$in;
}
