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Question by AlanMattano · Aug 14, 2017 at 06:03 PM · c#variablesif statementinfiniteinfinity

if statement for infinity. How to check if a variable is Infinity?

How do I check for "Infinity"?

Can I make an if statement for checking if the variable is returning infinity?

 if ( myVecto.x == infinity ) { ....

You can check if is returning infinity by printing in the console first. For example:

 if ( vectorForce.x > 100000f) Debug.Log( vectorForce.ToString());

And it will print in console something like this:

(Infinity, -Infinity, -Infinity)

But I can't make something like this

if (vectorForce.x == "Infinity") { <<<------------ RETURNS ERROR

Because my rigid body force assign attempt for 'myGameObject' is not valid. And the Input force is

{ Infinity, -Infinity, -Infinity }

And/or transform float or Vector assign attempt for my gameObject is not valid.

Input localScale is { Infinity, 0.500000, 0.500000 }.

THx!
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Answer by unidad2pete · Aug 14, 2017 at 06:18 PM

Try:

 if (vectorForce.x == Mathf.Infinity)
 {
     Debug.Log("infinity");
 }
 

or this:

 if (vectorForce.x.ToString() == Mathf.Infinity.ToString())
 {
     Debug.Log("infinity");
 }
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avatar image AlanMattano · Aug 16, 2017 at 04:25 PM 0
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And if the value is negative Infinity? The other answers options are correct in some way.

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Answer by Bunny83 · Aug 15, 2017 at 01:04 AM

If you don't care if the value is PositiveInfinity orNegativeInfinity you can simply use IsInfinity

 if(vectorForce.x.IsInfinity())

However if you want to distinguish between positive and negative infinity you would simply use:

 if(vectorForce.x == float.PositiveInfinity)
 // or
 if(vectorForce.x == float.NegativeInfinity)

IsInfinity will return true in both cases. Note: if the infinity value isn't expected by you, you might want to investigate where it actually comes from. Common causes are that you divided your vector by "0". Dividing a value different from 0 by zero doesn't result in an error but in positive or negative infinity.

So in general it's better to handle that situation before you divide. Note that when you divide 0 by 0 it will result in a NaN value instead as 0/0 is not defined.

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Answer by tanoshimi · Aug 14, 2017 at 06:19 PM

I don't quite understand the use case, but you can test whether a float value is at its max possible using:

 if(vectorForce.x == float.MaxValue)
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avatar image Bunny83 · Aug 15, 2017 at 01:06 AM 0
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Note: float.$$anonymous$$axValue is not the same as float.PositiveInfinity. $$anonymous$$axValue is the largest number that can still be represented by a float. Everything above that will yield PositiveInfinity.

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