koobas.hobune.stream
checking if 2 out of 4 is true no matter which one
Let's say that I have a switch statement like so
switch(id){
case 1:
break;
case 2:
break;
case 3:
break;
case 4:
break;
}
How can I detect in an easy manner without overloading my script with tons of code wether 2 out of these 4 are true, may it be 1 and 2 or 2 and 3 or 4 and 1, whenever 2 are true I need something to happen how can I achieve very easily and cleanly? (I know how to do it but I want a nice and clean way if possible)
Thanks!
Pleas note overloading is a specific technical term in computer program$$anonymous$$g. What you are doing has no relevance to overloading.
how can your "id" be equal to 2 different value at the same time ?
I think you need to be a little bit more precise about your question... How are you using it ?
Clean code is sometimes more a matter of formatting than approach. With four bool, there are only six states:
if ( ( a && b && !c && !d)
|| ( a && !b && c && !d)
|| ( a && !b && !c && d)
|| (!a && b && c && !d)
|| (!a && b && !c && d)
|| (!a && !b && c && d)
) {
And if the conditions was 'at least 2' rather than 'exactly 2', the condition would be substantially simpler.
Pseudo code
private bool[] bools = new bool[4];
private int count = 0;
foreach(bool myBool in bools){
if(myBool){
count++;
}
}
if (count>=2){
return true;
} else {
return false;
}
You can also add them to a list if you want to use named vars ins$$anonymous$$d of an array :)
Hi Jan,
I think the problem here is you want something that switch cannot provide. Basically switch is shorthand for an if-elseif block of code, thus your id variable can only be equal to a single case at any run through.
Without much more info, I can only give you a possible solution that may work.
int trueCounter;
if(id == case1) trueCounter++;
if(id == case2) trueCounter++;
if(id == case3) trueCounter++;
if(id == case4) trueCounter++;
if(trueCounter == 2)
{
// your stuff happens here
}
