Show / Hide GUI Button - Enable / Disable Script (Android)

Hello, I would like to create a button that appears when you press the screen , and it stays open until you press the button directly. The position of the button must be the same as the touch, I have tried to do something like this but I get an error (Index out of bounds) :

 public GameObject Test;

  void OnGUI()
     {

         TeleportClick script;
         script = Test.GetComponent<TeleportClick>();

         Touch touch;
         touch = Input.GetTouch(0);
 
         float x = touch.position.x;
         float y = Screen.height - touch.position.y;
 
         if (GUI.Button(new Rect(x, y, 300, 60), "Teleport"))
                 {
                     script.enabled = true;
                 }
             }
         }

After pressing the button , it must activate the script that once it is connected , run it (one time) and then turn it off. Finally hide the button.

This is the script that should be run only once after pressing the button (TeleportClick)

     private Transform player;
 
     void Awake()
     {
         player = GameObject.FindGameObjectWithTag("Player").transform;
     }
 
     void Update()
     {
         if (Input.touchCount == 1)
             player.position = Camera.main.ScreenToWorldPoint(Input.GetTouch(0).position);
     }
 }

Thanks in advance.