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Question by thunderdragonca · Dec 01, 2011 at 05:00 AM · openurl

Why the OPENURL doesn't really work?

I'm using Application.OpenURL() in my script. I have a variable in the script, and i'm using it in the link.

Example: var variable = blablabla Application.OpenURL("www.example.com/blablabla="+variable+"&blablabla")

But what i got is

www.example.com/blablabla=blablabla%26%238207%3B&blablabla

So strange, why there is %26%238207%3B after it? I'm confused, any suggestion?

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avatar image StephanK · Dec 01, 2011 at 09:49 AM 0
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What's the content of that variable? Does it contain empty spaces or special characters?

avatar image newborne · Jan 22, 2013 at 01:01 PM 0
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i am looking why openurl does not work with chrome native client

avatar image sonxoans2 · May 28, 2015 at 07:05 AM 0
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I'm using Application.OpenURL() in my script. I have a variable in the script, and i'm using it call sms in android. Application.OpenURL ("sms:" + port + "?body=content#content"); But what i got is: conent

behind # is lost. Why?

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Answer by Bunny83 · Jan 22, 2013 at 02:48 PM

Your actual variable value is

  ‏

just URL encoded because it contains "&", "#" and ";" characters. This is actually normal and each HTTP client should be able to read this URL parameter.

That is actually the HTML escaped version of the "right-to-left mark". If that's not what you expect you pass the variable in a wrong way i guess.

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