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Question by saman_kia · Apr 13, 2016 at 10:13 AM · inputinput.getkey

how we exit of my project with twice pressing back button???

Hi guys, i want to main scene my project with twice pressing back button mobile exit it for in work i use of code Input.GetKey (KeyCode.Escape) but this code with once pressing my project exit. does anyone know a way to give???? Thank you

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avatar image meat5000 ♦ · Apr 15, 2016 at 09:17 AM 0
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This will help you

http://docs.unity3d.com/ScriptReference/Input-backButtonLeavesApp.html

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Answer by aditya · Apr 13, 2016 at 10:19 AM

 uint exitCount = 0;
 void Update(){
     if(Input.GetKeyUp(KeyCode.ESCAPE)){
         exitCount++;
             if(!isInvoking("disableDoubleClick"))
                 invoke("disableDoubleClick", 0.3f);
     }
     if(exitCount == 2){
         CancelInvoke("disableDoubleClick");
         Application.Quit();
     }
 }
 
 void disableDoubleClick(){
     exitCount = 0;
 }

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avatar image fffMalzbier · Apr 13, 2016 at 10:21 AM 0
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Thanks for writing the code :)

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Answer by fffMalzbier · Apr 13, 2016 at 10:21 AM

You can start a small timer that counts the time from one Input.GetKey (KeyCode.Escape) to the next. if the exit key was pressed twice inside your designated time exit the application, if not do not exit.

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Answer by saman_kia · Apr 23, 2016 at 05:52 AM

Thanks to all friends

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