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Question by BonBonStudio · Aug 09, 2015 at 03:38 PM · ifshort

Short if statement

Hello guys, how can I shorten this if statement:

 if(1.7f >= angle && angle >= 1.4f || 8f >= angle && angle >= 7.7f || 14.3f >= angle && angle >= 14f || 20.6f >= angle && angle >= 20.3f || 26.9f >= angle && angle >= 26.6f || 33.2f >= angle && angle >= 32.9f || 39.5 >= angle && angle >= 39.2f || 45.8 >= angle && angle >= 45.5f)

Thanks in advance!

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Answer by allenallenallen · Aug 09, 2015 at 03:40 PM

The fact that you need it all to be in an if statement means you can't really simplify it. What you CAN do though is format it to be easier to read like so:

 if(1.7f >= angle && angle >= 1.4f || 
    8f >= angle && angle >= 7.7f ||
    14.3f >= angle && angle >= 14f ||
    20.6f >= angle && angle >= 20.3f ||
    26.9f >= angle && angle >= 26.6f ||
    33.2f >= angle && angle >= 32.9f ||
    39.5 >= angle && angle >= 39.2f ||
    45.8 >= angle && angle >= 45.5f){
 }
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avatar image BonBonStudio · Aug 09, 2015 at 03:50 PM 0
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Thanks for the quick response. But isn't it possible with an algorithm because the difference is every single time 6.3 => 45.8 - 39.5 = 6.3 39.5 - 33.2 = 6.3 ...

avatar image allenallenallen · Aug 09, 2015 at 04:00 PM 1
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Ah, I see what you meant. Here's the C# version of the algorithm.

 bool angleCheck(float angle){
 
     float start = 1.4f;
     float difference = 6.3f;
 
     for(int i = 0; i < 8; i++){
         if (start + 0.3f >= angle && angle >= start){
             return true;
         }
         start += difference;
     }
 
     return false;
 }

And the if statement is shortened to this:

 if (angleCheck(angle)){
 }


avatar image BonBonStudio · Aug 09, 2015 at 04:03 PM 0
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Thank you very much!

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Answer by sed · Aug 09, 2015 at 04:58 PM

Instead of looping you could use a modulo statement. This could be useful if the list you've provided is not complete (ie. it'd have to go on and on)

     bool angleCheck(float angle){
          float start = 1.4f;
          float difference = 6.3f;
          angle = angle % difference;
      
          if (start + 0.3f >= angle && angle >= start){
              return true;
          }
          
          return false;
      }

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avatar image allenallenallen · Aug 10, 2015 at 03:32 AM 1
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Never thought of it that way. I like it. A good solution for an infinite range test.

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