Quality Settings To Turn On Object

Question

Hello, I am trying to turn on an object based off of the quality setting, I have this script:

 var object1 : GameObject;
 
 function Awake ()
 {
     QualitySettings.GetQualityLevel();
 }
 
 function Update () 
 {
     if (QualityLevel.Fastest)
     {
         object1.gameObject.SetActive(true);
     }
 }

And I get no errors with it, even during runtime, however it is not working at all. I dont understand where I am going wrong.

Answer 1

Best Answer

Answer by Hexer · Jul 26, 2015 at 03:18 PM

That is strange, I have played with the code for a while with use of the unity reference and I made this script. (I made some mistake with saying LevelName, LevelName is not a member of QualitySettings so it didnt work. It should have been currentLevel. and you forgot to add another "=" ____1x"=" means Is. while 2x"=" mean is Equal to)

 using UnityEngine;
 using System.Collections;
 
 public class Test : MonoBehaviour {
 
     // Use this for initialization
     void Start () {
     
     }
     
     // Update is called once per frame
     void Update () {
         if (QualitySettings.currentLevel == QualityLevel.Fastest) {
             Application.LoadLevel ("1");
         } else 
             Application.LoadLevel ("2");
     }
 }

When I build and run this test project and put the quality to fastest. it would go to Apllication.LoadLevel("1"); and if some other quality was chosen, it would go to Application.LoadLevel("2");.

The same concept can also be applied to your script.

 if (QualitySettings.currentLevel == QualityLevel.Fastest) {
   object1.gameObject.SetActive(true);
 }

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sacajawhoohoo · Jul 27, 2015 at 04:40 AM 0

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I thought I had tried that before but it didnt work, retried it and it did, idk, but thank you for the help!

Quality Settings To Turn On Object

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